Day 83 of 180Week 17 of 36, WednesdaySecond quarter

Three dimensions

🔢 Math🔁 Practise⏱️ about 40 minutes

Find the diagonal of a box using the theorem twice.

Reps on something already met. Short, and worth doing even on a bad evening.

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Today is rung 4 of 7 on this topic

Pythagoras and irrational numbers

Can do: Applies the theorem in two and three dimensions and understands why √2 is irrational.

Why it matters

It's the first result they can genuinely prove, and it introduces numbers that cannot be written as fractions at all.

What it looks like when it's wobbly

Uses the theorem on non-right triangles, and treats the hypotenuse as whichever side is longest on the page.

⏱️ Two-minute check

"Legs 6 and 8 — find the hypotenuse. Is 0.333… rational? Is √2?"

Solid looks like: 10, yes, no.

The full activity for this topic · 25 minutes

Prove It With Squares

Squared paperScissorsRuler
  1. 1Draw a 3-4-5 triangle and build a square on each side.
  2. 2Count the squares: 9 + 16 = 25. The theorem is visible, not asserted.
  3. 3Try it on a non-right triangle and see the relationship fail.
  4. 4Use it for real: the diagonal of a room, whether a table fits through a door.
  5. 5Calculate √2 on a calculator and let the digits run — no pattern, no repeat, no fraction.

If it's too hard

Find the hypotenuse in whole-number triples.

If it's too easy

Find a missing leg, use it in 3-D for a box diagonal, and apply it on the coordinate plane.

Say this

"Where's the right angle? The hypotenuse is always opposite it — not just the longest-looking line."

Math practice

Week 17 at a glance

  1. Monday · Day 81

    🔢 Math

    Predict from the model

  2. Tuesday · Day 82

    📖 Reading

    Compare two authors

  3. Wednesday · Day 83

    🔢 Math

    Three dimensions

  4. Thursday · Day 84

    ✏️ Writing

    Revise for structure

  5. Friday · Day 85

    🧭 Study & Life Skills

    Write your own test

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